4(x+3)+2x=3(x-4)

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Solution for 4(x+3)+2x=3(x-4) equation: 



4(x+3)+2x=3(x-4)

We move all terms to the left:

4(x+3)+2x-(3(x-4))=0

We add all the numbers together, and all the variables

2x+4(x+3)-(3(x-4))=0

We multiply parentheses

2x+4x-(3(x-4))+12=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

6x-(3x-12)+12=0

We get rid of parentheses

6x-3x+12+12=0

We add all the numbers together, and all the variables

3x+24=0

We move all terms containing x to the left, all other terms to the right

3x=-24

x=-24/3

x=-8

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