3/2(-42+12)=1/2(2d-6)

Solution for 3/2(-42+12)=1/2(2d-6) equation:

3/2(-42+12)=1/2(2d-6)

We move all terms to the left:

3/2(-42+12)-(1/2(2d-6))=0


Domain of the equation: 2(2d-6))!=0

d∈R


We add all the numbers together, and all the variables

-(1/2(2d-6))+3/2(-30)=0

We calculate fractions


()/(2(2d-6))*2()+(6d2/(2(2d-6))*2()=0


We calculate terms in parentheses: +()/(2(2d-6))*2(), so:

)/(2(2d-6))*2(

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()



We calculate terms in parentheses: +(6d2/(2(2d-6))*2(), so:

6d2/(2(2d-6))*2(

We multiply all the terms by the denominator


6d2

We add all the numbers together, and all the variables

6d^2

Back to the equation:

+(6d^2)


We add all the numbers together, and all the variables

6d^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{12}=0$