5+2(k-12)=-11+4(9+k)

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Solution for 5+2(k-12)=-11+4(9+k) equation: 



5+2(k-12)=-11+4(9+k)

We move all terms to the left:

5+2(k-12)-(-11+4(9+k))=0

We add all the numbers together, and all the variables

2(k-12)-(-11+4(k+9))+5=0

We multiply parentheses

2k-(-11+4(k+9))-24+5=0



We calculate terms in parentheses: -(-11+4(k+9)), so:

-11+4(k+9)

determiningTheFunctionDomain
4(k+9)-11

We multiply parentheses

4k+36-11

We add all the numbers together, and all the variables

4k+25

Back to the equation:

-(4k+25)



We add all the numbers together, and all the variables

2k-(4k+25)-19=0

We get rid of parentheses

2k-4k-25-19=0

We add all the numbers together, and all the variables

-2k-44=0

We move all terms containing k to the left, all other terms to the right

-2k=44

k=44/-2

k=-22

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