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3/2(-2x+2)+9=-3+5(4x+2)
We move all terms to the left:
3/2(-2x+2)+9-(-3+5(4x+2))=0
Domain of the equation: 2(-2x+2)!=0We multiply all the terms by the denominator
x∈R
-((-3+5(4x+2)))*2(-2x+2)+9*2(-2x+2)+3=0
We calculate terms in parentheses: -((-3+5(4x+2)))*2(-2x+2), so:We add all the numbers together, and all the variables
(-3+5(4x+2)))*2(-2x+2
We add all the numbers together, and all the variables
-2x+(-3+5(4x+2)))*2(+2
Back to the equation:
-(-2x+(-3+5(4x+2)))*2(+2)
-(-2x+(-3+5(4x+2)))*22+9*2(-2x+2)+3=0
Wy multiply elements
-(-2x+(-3+5(4x+2)))*22+18x(-+3=0
We use the square of the difference formula
-(-2x+(-3+5(4x+2)))*22+18x(-3=0
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