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10(x+1)=5(3x-6)
We move all terms to the left:
10(x+1)-(5(3x-6))=0
We multiply parentheses
10x-(5(3x-6))+10=0
We calculate terms in parentheses: -(5(3x-6)), so:We get rid of parentheses
5(3x-6)
We multiply parentheses
15x-30
Back to the equation:
-(15x-30)
10x-15x+30+10=0
We add all the numbers together, and all the variables
-5x+40=0
We move all terms containing x to the left, all other terms to the right
-5x=-40
x=-40/-5
x=+8
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