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3/10f+24=4-1/5f
We move all terms to the left:
3/10f+24-(4-1/5f)=0
Domain of the equation: 10f!=0
f!=0/10
f!=0
f∈R
Domain of the equation: 5f)!=0We add all the numbers together, and all the variables
f!=0/1
f!=0
f∈R
3/10f-(-1/5f+4)+24=0
We get rid of parentheses
3/10f+1/5f-4+24=0
We calculate fractions
15f/50f^2+10f/50f^2-4+24=0
We add all the numbers together, and all the variables
15f/50f^2+10f/50f^2+20=0
We multiply all the terms by the denominator
15f+10f+20*50f^2=0
We add all the numbers together, and all the variables
25f+20*50f^2=0
Wy multiply elements
1000f^2+25f=0
a = 1000; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·1000·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*1000}=\frac{-50}{2000} =-1/40 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*1000}=\frac{0}{2000} =0 $
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