(2)4b+82=10(2)

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Solution for (2)4b+82=10(2) equation: 



(2)4b+82=10(2)

We move all terms to the left:

(2)4b+82-(10(2))=0

determiningTheFunctionDomain
24b+82-102=0

We add all the numbers together, and all the variables

24b-20=0

We move all terms containing b to the left, all other terms to the right

24b=20

b=20/24

b=5/6

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