3/10=(b+7)/20

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Solution for 3/10=(b+7)/20 equation: 



3/10=(b+7)/20

We move all terms to the left:

3/10-((b+7)/20)=0

We calculate fractions


(-((b+7)*10)/()+()/()=0



We calculate terms in parentheses: +(-((b+7)*10)/()+()/(), so:

-((b+7)*10)/()+()/(

We add all the numbers together, and all the variables

-((b+7)*10)/()+1

We multiply all the terms by the denominator


-((b+7)*10)+1*()



We calculate terms in parentheses: -((b+7)*10), so:

(b+7)*10

We multiply parentheses

10b+70

Back to the equation:

-(10b+70)



We add all the numbers together, and all the variables

-(10b+70)

We get rid of parentheses

-10b-70

Back to the equation:

+(-10b-70)



We get rid of parentheses

-10b-70=0

We move all terms containing b to the left, all other terms to the right

-10b=70

b=70/-10

b=-7

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