-3(1+n)-2n=6(n-2)

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Solution for -3(1+n)-2n=6(n-2) equation: 



-3(1+n)-2n=6(n-2)

We move all terms to the left:

-3(1+n)-2n-(6(n-2))=0

We add all the numbers together, and all the variables

-3(n+1)-2n-(6(n-2))=0

We add all the numbers together, and all the variables

-2n-3(n+1)-(6(n-2))=0

We multiply parentheses

-2n-3n-(6(n-2))-3=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We add all the numbers together, and all the variables

-5n-(6n-12)-3=0

We get rid of parentheses

-5n-6n+12-3=0

We add all the numbers together, and all the variables

-11n+9=0

We move all terms containing n to the left, all other terms to the right

-11n=-9

n=-9/-11

n=9/11

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