3/10=(b+11)/20

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Solution for 3/10=(b+11)/20 equation: 



3/10=(b+11)/20

We move all terms to the left:

3/10-((b+11)/20)=0

We calculate fractions


(-((b+11)*10)/()+()/()=0



We calculate terms in parentheses: +(-((b+11)*10)/()+()/(), so:

-((b+11)*10)/()+()/(

We add all the numbers together, and all the variables

-((b+11)*10)/()+1

We multiply all the terms by the denominator


-((b+11)*10)+1*()



We calculate terms in parentheses: -((b+11)*10), so:

(b+11)*10

We multiply parentheses

10b+110

Back to the equation:

-(10b+110)



We add all the numbers together, and all the variables

-(10b+110)

We get rid of parentheses

-10b-110

Back to the equation:

+(-10b-110)



We get rid of parentheses

-10b-110=0

We move all terms containing b to the left, all other terms to the right

-10b=110

b=110/-10

b=-11

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