3(m-4)=7(m+8)

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Solution for 3(m-4)=7(m+8) equation: 



3(m-4)=7(m+8)

We move all terms to the left:

3(m-4)-(7(m+8))=0

We multiply parentheses

3m-(7(m+8))-12=0



We calculate terms in parentheses: -(7(m+8)), so:

7(m+8)

We multiply parentheses

7m+56

Back to the equation:

-(7m+56)



We get rid of parentheses

3m-7m-56-12=0

We add all the numbers together, and all the variables

-4m-68=0

We move all terms containing m to the left, all other terms to the right

-4m=68

m=68/-4

m=-17

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