3/(4+x)=7/x

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Solution for 3/(4+x)=7/x equation: 



3/(4+x)=7/x

We move all terms to the left:

3/(4+x)-(7/x)=0



Domain of the equation: (4+x)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/(x+4)-(+7/x)=0

We get rid of parentheses

3/(x+4)-7/x=0

We calculate fractions


3x/(x^2+4x)+(-7x-28)/(x^2+4x)=0

We multiply all the terms by the denominator


3x+(-7x-28)=0

We get rid of parentheses

3x-7x-28=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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