3/(2x-3)=2/(x=5)

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Solution for 3/(2x-3)=2/(x=5) equation: 



3/(2x-3)=2/(x=5)

We move all terms to the left:

3/(2x-3)-(2/(x)=0



Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R





Domain of the equation: x!=0

x∈R



We calculate fractions


3x/(2x^2-3x)+(-(2*(2x-3))/(2x^2-3x)=0



We calculate terms in parentheses: +(-(2*(2x-3))/(2x^2-3x), so:

-(2*(2x-3))/(2x^2-3x

We multiply all the terms by the denominator


-(2*(2x-3))



We calculate terms in parentheses: -(2*(2x-3)), so:

2*(2x-3)

We multiply parentheses

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

-4x+6

Back to the equation:

+(-4x+6)



We get rid of parentheses

3x/(2x^2-3x)-4x+6=0

We multiply all the terms by the denominator


3x-4x*(2x^2-3x)+6*(2x^2-3x)=0

We multiply parentheses

-8x^3+12x^2+12x^2+3x-18x=0

We do not support expression: x^3

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