28=1/2(2x+4x-10)

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Solution for 28=1/2(2x+4x-10) equation: 



28=1/2(2x+4x-10)

We move all terms to the left:

28-(1/2(2x+4x-10))=0



Domain of the equation: 2(2x+4x-10))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(6x-10))+28=0

We multiply all the terms by the denominator


-(1+28*2(6x-10))=0



We calculate terms in parentheses: -(1+28*2(6x-10)), so:

1+28*2(6x-10)

determiningTheFunctionDomain
28*2(6x-10)+1

Wy multiply elements

56x(6+1

Back to the equation:

-(56x(6+1)



We add all the numbers together, and all the variables

-(56x7=0

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