3/(2x-1)+4/(2x+1)=7/2x

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Solution for 3/(2x-1)+4/(2x+1)=7/2x equation: 



3/(2x-1)+4/(2x+1)=7/2x

We move all terms to the left:

3/(2x-1)+4/(2x+1)-(7/2x)=0



Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R





Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/(2x-1)+4/(2x+1)-(+7/2x)=0

We get rid of parentheses

3/(2x-1)+4/(2x+1)-7/2x=0

We calculate fractions


(12x^2+6x)/((2x-1)*(2x+1)*2x)+(16x^2-8x)/((2x-1)*(2x+1)*2x)+(-7*(2x-1)*(2x+1))/((2x-1)*(2x+1)*2x)=0



We calculate terms in parentheses: +(12x^2+6x)/((2x-1)*(2x+1)*2x), so:

12x^2+6x)/((2x-1)*(2x+1)*2x

We multiply all the terms by the denominator


12x^2*((2x-1)*(2x+1)*2x+6x)

Back to the equation:

+(12x^2*((2x-1)*(2x+1)*2x+6x))





We calculate terms in parentheses: +(16x^2-8x)/((2x-1)*(2x+1)*2x), so:

16x^2-8x)/((2x-1)*(2x+1)*2x

We multiply all the terms by the denominator


16x^2*((2x-1)*(2x+1)*2x-8x)

Back to the equation:

+(16x^2*((2x-1)*(2x+1)*2x-8x))





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))/((2x-1)*(2x+1)*2x), so:

-7*(2x-1)*(2x+1))/((2x-1)*(2x+1)*2x

We multiply all the terms by the denominator


-7*(2x-1)*(2x+1))

Back to the equation:

+(-7*(2x-1)*(2x+1)))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate terms in parentheses: +(12x^2*((2x-1)*(2x+1)*2x+6x)), so:

12x^2*((2x-1)*(2x+1)*2x+6x)





We calculate terms in parentheses: +(16x^2*((2x-1)*(2x+1)*2x-8x)), so:

16x^2*((2x-1)*(2x+1)*2x-8x)





We calculate terms in parentheses: +(-7*(2x-1)*(2x+1))), so:

-7*(2x-1)*(2x+1))





We calculate

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