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3-x=2x(5x-1)
We move all terms to the left:
3-x-(2x(5x-1))=0
We add all the numbers together, and all the variables
-1x-(2x(5x-1))+3=0
We calculate terms in parentheses: -(2x(5x-1)), so:We get rid of parentheses
2x(5x-1)
We multiply parentheses
10x^2-2x
Back to the equation:
-(10x^2-2x)
-10x^2-1x+2x+3=0
We add all the numbers together, and all the variables
-10x^2+x+3=0
a = -10; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-10)·3
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-10}=\frac{-12}{-20} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-10}=\frac{10}{-20} =-1/2 $
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