3-x(3x-3)=2x(2x-1+2x-)

Solution for 3-x(3x-3)=2x(2x-1+2x-) equation:

3-x(3x-3)=2x(2x-1+2x-)

We move all terms to the left:

3-x(3x-3)-(2x(2x-1+2x-))=0

We add all the numbers together, and all the variables

-x(3x-3)-(2x(+4x))+3=0

We multiply parentheses

-3x^2+3x-(2x(+4x))+3=0


We calculate terms in parentheses: -(2x(+4x)), so:

2x(+4x)

We multiply parentheses

8x^2

Back to the equation:

-(8x^2)


determiningTheFunctionDomain
-3x^2-8x^2+3x+3=0

We add all the numbers together, and all the variables

-11x^2+3x+3=0

a = -11; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-11)·3
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{141}}{2*-11}=\frac{-3-\sqrt{141}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{141}}{2*-11}=\frac{-3+\sqrt{141}}{-22}
$