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1/5x=1-3/10x
We move all terms to the left:
1/5x-(1-3/10x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(-3/10x+1)=0
We get rid of parentheses
1/5x+3/10x-1=0
We calculate fractions
10x/50x^2+15x/50x^2-1=0
We multiply all the terms by the denominator
10x+15x-1*50x^2=0
We add all the numbers together, and all the variables
25x-1*50x^2=0
Wy multiply elements
-50x^2+25x=0
a = -50; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-50)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-50}=\frac{-50}{-100} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-50}=\frac{0}{-100} =0 $
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