3-a(8-2a)=-1

Solution for 3-a(8-2a)=-1 equation:

3-a(8-2a)=-1

We move all terms to the left:

3-a(8-2a)-(-1)=0

We add all the numbers together, and all the variables

-a(-2a+8)+3-(-1)=0

We add all the numbers together, and all the variables

-a(-2a+8)+4=0

We multiply parentheses

2a^2-8a+4=0

a = 2; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·2·4
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{2}}{2*2}=\frac{8-4\sqrt{2}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{2}}{2*2}=\frac{8+4\sqrt{2}}{4}
$