3-7x=4(3x-2x-12)

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Solution for 3-7x=4(3x-2x-12) equation: 



3-7x=4(3x-2x-12)

We move all terms to the left:

3-7x-(4(3x-2x-12))=0

We add all the numbers together, and all the variables

-7x-(4(x-12))+3=0



We calculate terms in parentheses: -(4(x-12)), so:

4(x-12)

We multiply parentheses

4x-48

Back to the equation:

-(4x-48)



We get rid of parentheses

-7x-4x+48+3=0

We add all the numbers together, and all the variables

-11x+51=0

We move all terms containing x to the left, all other terms to the right

-11x=-51

x=-51/-11

x=4+7/11

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