3-7x=3(x-2)+2(x-1)-4

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Solution for 3-7x=3(x-2)+2(x-1)-4 equation: 



3-7x=3(x-2)+2(x-1)-4

We move all terms to the left:

3-7x-(3(x-2)+2(x-1)-4)=0



We calculate terms in parentheses: -(3(x-2)+2(x-1)-4), so:

3(x-2)+2(x-1)-4

We multiply parentheses

3x+2x-6-2-4

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

-7x-5x+12+3=0

We add all the numbers together, and all the variables

-12x+15=0

We move all terms containing x to the left, all other terms to the right

-12x=-15

x=-15/-12

x=1+1/4

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