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2/3(6x+12)-13=9-2(7-2x)
We move all terms to the left:
2/3(6x+12)-13-(9-2(7-2x))=0
Domain of the equation: 3(6x+12)!=0We add all the numbers together, and all the variables
x∈R
2/3(6x+12)-(9-2(-2x+7))-13=0
We multiply all the terms by the denominator
-((9-2(-2x+7)))*3(6x+12)-13*3(6x+12)+2=0
We calculate terms in parentheses: -((9-2(-2x+7)))*3(6x+12), so:Wy multiply elements
(9-2(-2x+7)))*3(6x+12
-((9-2(-2x+7)))*3(6x+12)-39x(6+2=0
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