3-7x-(1-x)=2(x+1)

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Solution for 3-7x-(1-x)=2(x+1) equation: 



3-7x-(1-x)=2(x+1)

We move all terms to the left:

3-7x-(1-x)-(2(x+1))=0

We add all the numbers together, and all the variables

-7x-(-1x+1)-(2(x+1))+3=0

We get rid of parentheses

-7x+1x-(2(x+1))-1+3=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

-6x-(2x+2)+2=0

We get rid of parentheses

-6x-2x-2+2=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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