180=(5x+3x)+(3x+20)+(10x+30)

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Solution for 180=(5x+3x)+(3x+20)+(10x+30) equation: 



180=(5x+3x)+(3x+20)+(10x+30)

We move all terms to the left:

180-((5x+3x)+(3x+20)+(10x+30))=0

We add all the numbers together, and all the variables

-((+8x)+(3x+20)+(10x+30))+180=0



We calculate terms in parentheses: -((+8x)+(3x+20)+(10x+30)), so:

(+8x)+(3x+20)+(10x+30)

We get rid of parentheses

8x+3x+10x+20+30

We add all the numbers together, and all the variables

21x+50

Back to the equation:

-(21x+50)



We get rid of parentheses

-21x-50+180=0

We add all the numbers together, and all the variables

-21x+130=0

We move all terms containing x to the left, all other terms to the right

-21x=-130

x=-130/-21

x=6+4/21

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