(-4+y)/2=(12-5y)/6

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Solution for (-4+y)/2=(12-5y)/6 equation: 



(-4+y)/2=(12-5y)/6

We move all terms to the left:

(-4+y)/2-((12-5y)/6)=0

We add all the numbers together, and all the variables

(y-4)/2-((-5y+12)/6)=0

We calculate fractions


y/()+(-((-5y+12)*2)/()=0



We calculate terms in parentheses: +(-((-5y+12)*2)/(), so:

-((-5y+12)*2)/(

We multiply all the terms by the denominator


-((-5y+12)*2)



We calculate terms in parentheses: -((-5y+12)*2), so:

(-5y+12)*2

We multiply parentheses

-10y+24

Back to the equation:

-(-10y+24)



We get rid of parentheses

10y-24

Back to the equation:

+(10y-24)



We get rid of parentheses

y/()+10y-24=0

We multiply all the terms by the denominator


y+10y*()-24*()=0

We add all the numbers together, and all the variables

y+10y*()=0

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