3-6(x-1)=9-2(1+3x)+2x

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Solution for 3-6(x-1)=9-2(1+3x)+2x equation: 



3-6(x-1)=9-2(1+3x)+2x

We move all terms to the left:

3-6(x-1)-(9-2(1+3x)+2x)=0

We add all the numbers together, and all the variables

-6(x-1)-(9-2(3x+1)+2x)+3=0

We multiply parentheses

-6x-(9-2(3x+1)+2x)+6+3=0



We calculate terms in parentheses: -(9-2(3x+1)+2x), so:

9-2(3x+1)+2x

determiningTheFunctionDomain
-2(3x+1)+2x+9

We add all the numbers together, and all the variables

2x-2(3x+1)+9

We multiply parentheses

2x-6x-2+9

We add all the numbers together, and all the variables

-4x+7

Back to the equation:

-(-4x+7)



We add all the numbers together, and all the variables

-6x-(-4x+7)+9=0

We get rid of parentheses

-6x+4x-7+9=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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