(2x-5)(x+3)-3x=8-x+(3-x)(5-2x)

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Solution for (2x-5)(x+3)-3x=8-x+(3-x)(5-2x) equation: 



(2x-5)(x+3)-3x=8-x+(3-x)(5-2x)

We move all terms to the left:

(2x-5)(x+3)-3x-(8-x+(3-x)(5-2x))=0

We add all the numbers together, and all the variables

(2x-5)(x+3)-3x-(8-x+(-1x+3)(-2x+5))=0

We add all the numbers together, and all the variables

-3x+(2x-5)(x+3)-(8-x+(-1x+3)(-2x+5))=0

We multiply parentheses ..

(+2x^2+6x-5x-15)-3x-(8-x+(-1x+3)(-2x+5))=0



We calculate terms in parentheses: -(8-x+(-1x+3)(-2x+5)), so:

8-x+(-1x+3)(-2x+5)

determiningTheFunctionDomain
-x+(-1x+3)(-2x+5)+8

We add all the numbers together, and all the variables

-1x+(-1x+3)(-2x+5)+8

We multiply parentheses ..

(+2x^2-5x-6x+15)-1x+8

We get rid of parentheses

2x^2-5x-6x-1x+15+8

We add all the numbers together, and all the variables

2x^2-12x+23

Back to the equation:

-(2x^2-12x+23)



We get rid of parentheses

2x^2-2x^2+6x-5x-3x+12x-15-23=0

We add all the numbers together, and all the variables

10x-38=0

We move all terms containing x to the left, all other terms to the right

10x=38

x=38/10

x=3+4/5

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