3(6-x)+2(x-3)=5+2(3x+1)-1

Solution for 3(6-x)+2(x-3)=5+2(3x+1)-1 equation:

3(6-x)+2(x-3)=5+2(3x+1)-1

We move all terms to the left:

3(6-x)+2(x-3)-(5+2(3x+1)-1)=0

We add all the numbers together, and all the variables

3(-1x+6)+2(x-3)-(5+2(3x+1)-1)=0

We multiply parentheses

-3x+2x-(5+2(3x+1)-1)+18-6=0


We calculate terms in parentheses: -(5+2(3x+1)-1), so:

5+2(3x+1)-1

determiningTheFunctionDomain
2(3x+1)+5-1

We add all the numbers together, and all the variables

2(3x+1)+4

We multiply parentheses

6x+2+4

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)


We add all the numbers together, and all the variables

-1x-(6x+6)+12=0

We get rid of parentheses

-1x-6x-6+12=0

We add all the numbers together, and all the variables

-7x+6=0

We move all terms containing x to the left, all other terms to the right

-7x=-6

x=-6/-7

x=6/7