3-5k+2k=-2-2(1-k)

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Solution for 3-5k+2k=-2-2(1-k) equation: 



3-5k+2k=-2-2(1-k)

We move all terms to the left:

3-5k+2k-(-2-2(1-k))=0

We add all the numbers together, and all the variables

-5k+2k-(-2-2(-1k+1))+3=0

We add all the numbers together, and all the variables

-3k-(-2-2(-1k+1))+3=0



We calculate terms in parentheses: -(-2-2(-1k+1)), so:

-2-2(-1k+1)

determiningTheFunctionDomain
-2(-1k+1)-2

We multiply parentheses

2k-2-2

We add all the numbers together, and all the variables

2k-4

Back to the equation:

-(2k-4)



We get rid of parentheses

-3k-2k+4+3=0

We add all the numbers together, and all the variables

-5k+7=0

We move all terms containing k to the left, all other terms to the right

-5k=-7

k=-7/-5

k=1+2/5

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