3-5(y-1)=2+(y-4)

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Solution for 3-5(y-1)=2+(y-4) equation:



3-5(y-1)=2+(y-4)
We move all terms to the left:
3-5(y-1)-(2+(y-4))=0
We multiply parentheses
-5y-(2+(y-4))+5+3=0
We calculate terms in parentheses: -(2+(y-4)), so:
2+(y-4)
determiningTheFunctionDomain (y-4)+2
We get rid of parentheses
y-4+2
We add all the numbers together, and all the variables
y-2
Back to the equation:
-(y-2)
We add all the numbers together, and all the variables
-5y-(y-2)+8=0
We get rid of parentheses
-5y-y+2+8=0
We add all the numbers together, and all the variables
-6y+10=0
We move all terms containing y to the left, all other terms to the right
-6y=-10
y=-10/-6
y=1+2/3

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