14=(1/2h)(6+1)

Solution for 14=(1/2h)(6+1) equation:

14=(1/2h)(6+1)

We move all terms to the left:

14-((1/2h)(6+1))=0


Domain of the equation: 2h)(6+1))!=0

h∈R


We add all the numbers together, and all the variables

-((+1/2h)7)+14=0

We multiply all the terms by the denominator


-((+1+14*2h)7)=0


We calculate terms in parentheses: -((+1+14*2h)7), so:

(+1+14*2h)7

We add all the numbers together, and all the variables

(14*2h+1)7

We multiply parentheses

196h+7

Back to the equation:

-(196h+7)


We get rid of parentheses

-196h-7=0

We move all terms containing h to the left, all other terms to the right

-196h=7

h=7/-196

h=-1/28