3-4(b+2)=13-b

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Solution for 3-4(b+2)=13-b equation: 



3-4(b+2)=13-b

We move all terms to the left:

3-4(b+2)-(13-b)=0

We add all the numbers together, and all the variables

-4(b+2)-(-1b+13)+3=0

We multiply parentheses

-4b-(-1b+13)-8+3=0

We get rid of parentheses

-4b+1b-13-8+3=0

We add all the numbers together, and all the variables

-3b-18=0

We move all terms containing b to the left, all other terms to the right

-3b=18

b=18/-3

b=-6

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