9+5(b+2)=13-b

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Solution for 9+5(b+2)=13-b equation: 



9+5(b+2)=13-b

We move all terms to the left:

9+5(b+2)-(13-b)=0

We add all the numbers together, and all the variables

5(b+2)-(-1b+13)+9=0

We multiply parentheses

5b-(-1b+13)+10+9=0

We get rid of parentheses

5b+1b-13+10+9=0

We add all the numbers together, and all the variables

6b+6=0

We move all terms containing b to the left, all other terms to the right

6b=-6

b=-6/6

b=-1

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