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3-2x=1/2x-5
We move all terms to the left:
3-2x-(1/2x-5)=0
Domain of the equation: 2x-5)!=0We get rid of parentheses
x∈R
-2x-1/2x+5+3=0
We multiply all the terms by the denominator
-2x*2x+5*2x+3*2x-1=0
Wy multiply elements
-4x^2+10x+6x-1=0
We add all the numbers together, and all the variables
-4x^2+16x-1=0
a = -4; b = 16; c = -1;
Δ = b2-4ac
Δ = 162-4·(-4)·(-1)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{15}}{2*-4}=\frac{-16-4\sqrt{15}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{15}}{2*-4}=\frac{-16+4\sqrt{15}}{-8} $
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