-(12-6z)=-6(3z+14)

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Solution for -(12-6z)=-6(3z+14) equation: 



-(12-6z)=-6(3z+14)

We move all terms to the left:

-(12-6z)-(-6(3z+14))=0

We add all the numbers together, and all the variables

-(-6z+12)-(-6(3z+14))=0

We get rid of parentheses

6z-(-6(3z+14))-12=0



We calculate terms in parentheses: -(-6(3z+14)), so:

-6(3z+14)

We multiply parentheses

-18z-84

Back to the equation:

-(-18z-84)



We get rid of parentheses

6z+18z+84-12=0

We add all the numbers together, and all the variables

24z+72=0

We move all terms containing z to the left, all other terms to the right

24z=-72

z=-72/24

z=-3

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