3-(x-4)=10(x+11)

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Solution for 3-(x-4)=10(x+11) equation: 



3-(x-4)=10(x+11)

We move all terms to the left:

3-(x-4)-(10(x+11))=0

We get rid of parentheses

-x-(10(x+11))+4+3=0



We calculate terms in parentheses: -(10(x+11)), so:

10(x+11)

We multiply parentheses

10x+110

Back to the equation:

-(10x+110)



We add all the numbers together, and all the variables

-1x-(10x+110)+7=0

We get rid of parentheses

-1x-10x-110+7=0

We add all the numbers together, and all the variables

-11x-103=0

We move all terms containing x to the left, all other terms to the right

-11x=103

x=103/-11

x=-9+4/11

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