17b2+19B=10

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Solution for 17b2+19B=10 equation: 



17b^2+19=10

We move all terms to the left:

17b^2+19-(10)=0

We add all the numbers together, and all the variables

17b^2+9=0

a = 17; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·17·9
Δ = -612
Delta is less than zero, so there is no solution for the equation

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