3-(w+1)+7=4(w+1)-5

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Solution for 3-(w+1)+7=4(w+1)-5 equation: 



3-(w+1)+7=4(w+1)-5

We move all terms to the left:

3-(w+1)+7-(4(w+1)-5)=0

We add all the numbers together, and all the variables

-(w+1)-(4(w+1)-5)+10=0

We get rid of parentheses

-w-(4(w+1)-5)-1+10=0



We calculate terms in parentheses: -(4(w+1)-5), so:

4(w+1)-5

We multiply parentheses

4w+4-5

We add all the numbers together, and all the variables

4w-1

Back to the equation:

-(4w-1)



We add all the numbers together, and all the variables

-1w-(4w-1)+9=0

We get rid of parentheses

-1w-4w+1+9=0

We add all the numbers together, and all the variables

-5w+10=0

We move all terms containing w to the left, all other terms to the right

-5w=-10

w=-10/-5

w=+2

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