7(3x-2)=28-3(x-2)

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Solution for 7(3x-2)=28-3(x-2) equation: 



7(3x-2)=28-3(x-2)

We move all terms to the left:

7(3x-2)-(28-3(x-2))=0

We multiply parentheses

21x-(28-3(x-2))-14=0



We calculate terms in parentheses: -(28-3(x-2)), so:

28-3(x-2)

determiningTheFunctionDomain
-3(x-2)+28

We multiply parentheses

-3x+6+28

We add all the numbers together, and all the variables

-3x+34

Back to the equation:

-(-3x+34)



We get rid of parentheses

21x+3x-34-14=0

We add all the numbers together, and all the variables

24x-48=0

We move all terms containing x to the left, all other terms to the right

24x=48

x=48/24

x=2

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