3-(r/8)=-(9/2)

Solution for 3-(r/8)=-(9/2) equation:

3-(r/8)=-(9/2)

We move all terms to the left:

3-(r/8)-(-(9/2))=0

We add all the numbers together, and all the variables

-(+r/8)+3-(-(+9/2))=0

We get rid of parentheses

-r/8+3-(-(+9/2))=0

We calculate fractions


(-2r^2)/()+3+()/()=0

We add all the numbers together, and all the variables

(-2r^2)/()+4=0

We multiply all the terms by the denominator


(-2r^2)+4*()=0

We add all the numbers together, and all the variables

(-2r^2)=0

We get rid of parentheses

-2r^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-4}=0$