5(7-2x)=6(3x+1)-(4-27x)

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Solution for 5(7-2x)=6(3x+1)-(4-27x) equation: 



5(7-2x)=6(3x+1)-(4-27x)

We move all terms to the left:

5(7-2x)-(6(3x+1)-(4-27x))=0

We add all the numbers together, and all the variables

5(-2x+7)-(6(3x+1)-(-27x+4))=0

We multiply parentheses

-10x-(6(3x+1)-(-27x+4))+35=0



We calculate terms in parentheses: -(6(3x+1)-(-27x+4)), so:

6(3x+1)-(-27x+4)

We multiply parentheses

18x-(-27x+4)+6

We get rid of parentheses

18x+27x-4+6

We add all the numbers together, and all the variables

45x+2

Back to the equation:

-(45x+2)



We get rid of parentheses

-10x-45x-2+35=0

We add all the numbers together, and all the variables

-55x+33=0

We move all terms containing x to the left, all other terms to the right

-55x=-33

x=-33/-55

x=3/5

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