3,000=17x2+20x

Solution for 3,000=17x2+20x equation:

3.000=17x^2+20x

We move all terms to the left:

3.000-(17x^2+20x)=0

We add all the numbers together, and all the variables

-(17x^2+20x)+3=0

We get rid of parentheses

-17x^2-20x+3=0

a = -17; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·(-17)·3
Δ = 604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{604}=\sqrt{4*151}=\sqrt{4}*\sqrt{151}=2\sqrt{151}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{151}}{2*-17}=\frac{20-2\sqrt{151}}{-34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{151}}{2*-17}=\frac{20+2\sqrt{151}}{-34}
$