1.6=-3t2+18t+48

Solution for 1.6=-3t2+18t+48 equation:

1.6=-3t^2+18t+48

We move all terms to the left:

1.6-(-3t^2+18t+48)=0

We get rid of parentheses

3t^2-18t-48+1.6=0

We add all the numbers together, and all the variables

3t^2-18t-46.4=0

a = 3; b = -18; c = -46.4;
Δ = b2-4ac
Δ = -182-4·3·(-46.4)
Δ = 880.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{880.8}}{2*3}=\frac{18-\sqrt{880.8}}{6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{880.8}}{2*3}=\frac{18+\sqrt{880.8}}{6}
$