3+5(2y-1)=-2(6y-2)+7y

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Solution for 3+5(2y-1)=-2(6y-2)+7y equation: 



3+5(2y-1)=-2(6y-2)+7y

We move all terms to the left:

3+5(2y-1)-(-2(6y-2)+7y)=0

We multiply parentheses

10y-(-2(6y-2)+7y)-5+3=0



We calculate terms in parentheses: -(-2(6y-2)+7y), so:

-2(6y-2)+7y

We add all the numbers together, and all the variables

7y-2(6y-2)

We multiply parentheses

7y-12y+4

We add all the numbers together, and all the variables

-5y+4

Back to the equation:

-(-5y+4)



We add all the numbers together, and all the variables

10y-(-5y+4)-2=0

We get rid of parentheses

10y+5y-4-2=0

We add all the numbers together, and all the variables

15y-6=0

We move all terms containing y to the left, all other terms to the right

15y=6

y=6/15

y=2/5

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