-2(5y-2)+2y=4(y+3)

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Solution for -2(5y-2)+2y=4(y+3) equation: 



-2(5y-2)+2y=4(y+3)

We move all terms to the left:

-2(5y-2)+2y-(4(y+3))=0

We add all the numbers together, and all the variables

2y-2(5y-2)-(4(y+3))=0

We multiply parentheses

2y-10y-(4(y+3))+4=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

-8y-(4y+12)+4=0

We get rid of parentheses

-8y-4y-12+4=0

We add all the numbers together, and all the variables

-12y-8=0

We move all terms containing y to the left, all other terms to the right

-12y=8

y=8/-12

y=-2/3

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