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3+4x=(12x+9)/3
We move all terms to the left:
3+4x-((12x+9)/3)=0
We multiply all the terms by the denominator
4x*3)-((12x+9)+3*3)=0
We add all the numbers together, and all the variables
4x*3)-((12x+9)=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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