(A+3)+(2a-5)=78

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Solution for (A+3)+(2a-5)=78 equation: 



(+3)+(2A-5)=78

We move all terms to the left:

(+3)+(2A-5)-(78)=0

determiningTheFunctionDomain
(2A-5)-78+(+3)=0

We add all the numbers together, and all the variables

(2A-5)-78+3=0

We add all the numbers together, and all the variables

(2A-5)-75=0

We get rid of parentheses

2A-5-75=0

We add all the numbers together, and all the variables

2A-80=0

We move all terms containing A to the left, all other terms to the right

2A=80

A=80/2

A=40

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