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3+4/6x=6-1/3x
We move all terms to the left:
3+4/6x-(6-1/3x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/6x-(-1/3x+6)+3=0
We get rid of parentheses
4/6x+1/3x-6+3=0
We calculate fractions
12x/18x^2+6x/18x^2-6+3=0
We add all the numbers together, and all the variables
12x/18x^2+6x/18x^2-3=0
We multiply all the terms by the denominator
12x+6x-3*18x^2=0
We add all the numbers together, and all the variables
18x-3*18x^2=0
Wy multiply elements
-54x^2+18x=0
a = -54; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-54)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-54}=\frac{-36}{-108} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-54}=\frac{0}{-108} =0 $
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