n-1=5n-4(n+1)+3

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Solution for n-1=5n-4(n+1)+3 equation: 



n-1=5n-4(n+1)+3

We move all terms to the left:

n-1-(5n-4(n+1)+3)=0



We calculate terms in parentheses: -(5n-4(n+1)+3), so:

5n-4(n+1)+3

We multiply parentheses

5n-4n-4+3

We add all the numbers together, and all the variables

n-1

Back to the equation:

-(n-1)



We get rid of parentheses

n-n+1-1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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