3+4(4x-5)=7-5(2x+1)

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Solution for 3+4(4x-5)=7-5(2x+1) equation:



3+4(4x-5)=7-5(2x+1)
We move all terms to the left:
3+4(4x-5)-(7-5(2x+1))=0
We multiply parentheses
16x-(7-5(2x+1))-20+3=0
We calculate terms in parentheses: -(7-5(2x+1)), so:
7-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+7
We multiply parentheses
-10x-5+7
We add all the numbers together, and all the variables
-10x+2
Back to the equation:
-(-10x+2)
We add all the numbers together, and all the variables
16x-(-10x+2)-17=0
We get rid of parentheses
16x+10x-2-17=0
We add all the numbers together, and all the variables
26x-19=0
We move all terms containing x to the left, all other terms to the right
26x=19
x=19/26
x=19/26

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